34. Distribution Comparison

Note

本附录章用随机占优 (stochastic dominance) 比较两个随机变量 \(X,Y\) 的分布。一阶随机占优 (FOSD):对所有递增效用 \(u\) 都有 \(\int u\,dF_X\ge\int u\,dF_Y\)(即所有人都更偏好 \(X\));二阶随机占优 (SOSD):对所有递增且凹的 \(u\)(即所有风险厌恶者)成立——故 FOSD 蕴含 SOSD(Remark 34.1)。均值保持展宽 (mean-preserving spread, MPS):\(F_Y\) 是 \(F_X\) 的 MPS 当 \(\mathbb E[X]=\mathbb E[Y]\) 但 \(\operatorname{Var}(Y)>\operatorname{Var}(X)\);充分条件 \(Y=X+\varepsilon\) 且 \(\mathbb E[\varepsilon\mid X]=0\)(Prop 34.1:同均值由迭代期望、更大方差因 \(\mathbb E[\varepsilon^2]>0\))。核心定理 34.1:若 \(\mathbb E[Y\mid X]=X\),则 \(F_X\ge_{\text{SOSD}}F_Y\)——证明用迭代期望 + Jensen 不等式(对凹 \(u\))得 \(\mathbb E[u(Y)]\le\mathbb E[u(X)]\)。直觉(Remark 34.2):风险厌恶者不喜欢均值保持展宽。应用 (Example 34.1):\(N\) 个 i.i.d. 毛收益资产中,等权组合 \(Y^\star=\frac1N\sum R_i\) 对任意风险厌恶者都是最优的——因对任意组合 \(Y=\sum w_iR_i\) 都有 \(\mathbb E[Y\mid Y^\star]=Y^\star\),故 \(F_{Y^\star}\ge_{\text{SOSD}}F_Y\)。

Note

This appendix chapter uses stochastic dominance to compare the distributions of two random variables \(X,Y\). First-order stochastic dominance (FOSD): \(\int u\,dF_X\ge\int u\,dF_Y\) for all increasing utilities \(u\) (everyone prefers \(X\)); second-order stochastic dominance (SOSD): holds for all increasing and concave \(u\) (all risk-averse agents) — hence FOSD implies SOSD (Remark 34.1). A mean-preserving spread (MPS): \(F_Y\) is an MPS of \(F_X\) when \(\mathbb E[X]=\mathbb E[Y]\) but \(\operatorname{Var}(Y)>\operatorname{Var}(X)\); a sufficient condition is \(Y=X+\varepsilon\) with \(\mathbb E[\varepsilon\mid X]=0\) (Prop 34.1: same mean by iterated expectation, larger variance since \(\mathbb E[\varepsilon^2]>0\)). The core theorem 34.1: if \(\mathbb E[Y\mid X]=X\), then \(F_X\ge_{\text{SOSD}}F_Y\) — proven via iterated expectation + Jensen's inequality (for concave \(u\)) to get \(\mathbb E[u(Y)]\le\mathbb E[u(X)]\). Intuition (Remark 34.2): risk-averse agents dislike mean-preserving spreads. Application (Example 34.1): among \(N\) i.i.d. gross-return assets, the equal-weight portfolio \(Y^\star=\frac1N\sum R_i\) is optimal for any risk-averse agent — because for any portfolio \(Y=\sum w_iR_i\) we have \(\mathbb E[Y\mid Y^\star]=Y^\star\), hence \(F_{Y^\star}\ge_{\text{SOSD}}F_Y\).

34.1 First-Order and Second-Order Stochastic Dominance

考虑 \(\mathbb R\) 上的两个随机变量 \(X\) 与 \(Y\),c.d.f. 分别为 \(F_X\)、\(F_Y\)。

Definition 34.1(一阶随机占优 FOSD):称 \(F_X\) 一阶随机占优 \(F_Y\),记 \(F_X\ge_{\text{FOSD}}F_Y\),若对所有递增函数 \(u:\mathbb R\to\mathbb R\),

Consider two random variables \(X\) and \(Y\) on \(\mathbb R\), with c.d.f.s \(F_X\) and \(F_Y\) respectively.

Definition 34.1 (FOSD): \(F_X\) first-order stochastically dominates \(F_Y\), written \(F_X\ge_{\text{FOSD}}F_Y\), if for all increasing functions \(u:\mathbb R\to\mathbb R\),

$$\int u(x)\,dF_X(x)\ \ge\ \int u(y)\,dF_Y(y)$$

(等价刻画:\(F_X(w)\le F_Y(w)\) 对所有 \(w\) 成立——这两个定义等价。)

Definition 34.2(二阶随机占优 SOSD):称 \(F_X\) 二阶随机占优 \(F_Y\),记 \(F_X\ge_{\text{SOSD}}F_Y\),若对所有递增且凹的函数 \(u:\mathbb R\to\mathbb R\),

(Equivalent characterization: \(F_X(w)\le F_Y(w)\) for all \(w\) — these two definitions are equivalent.)

Definition 34.2 (SOSD): \(F_X\) second-order stochastically dominates \(F_Y\), written \(F_X\ge_{\text{SOSD}}F_Y\), if for all increasing and concave functions \(u:\mathbb R\to\mathbb R\),

$$\int u(x)\,dF_X(x)\ \ge\ \int u(y)\,dF_Y(y)$$

Tip

Remark 34.1 FOSD 蕴含 SOSD。因为递增且凹的 \(u\) 是「所有递增 \(u\)」的子集——若不等式对所有递增 \(u\) 成立,自然对其中递增且凹的那部分成立。直觉:FOSD(人人偏好 \(X\))比 SOSD(仅风险厌恶者偏好 \(X\))更强。

34.2 Mean-Preserving Spread

Definition 34.3(均值保持展宽 MPS):对任意彩票(分布)\(F_X,F_Y\),称 \(F_Y\) 是 \(F_X\) 的均值保持展宽,若(\(X\sim F_X\)、\(Y\sim F_Y\))

Tip

Remark 34.1 FOSD implies SOSD. Because increasing concave \(u\) is a subset of "all increasing \(u\)" — if the inequality holds for all increasing \(u\), it naturally holds for the increasing concave ones among them. Intuition: FOSD (everyone prefers \(X\)) is stronger than SOSD (only risk-averse agents prefer \(X\)).

34.2 Mean-Preserving Spread

Definition 34.3 (MPS): for any lotteries (distributions) \(F_X,F_Y\), we say \(F_Y\) is a mean-preserving spread of \(F_X\) if (with \(X\sim F_X\), \(Y\sim F_Y\))

$$\mathbb E[X]=\mathbb E[Y]\qquad\text{and}\qquad\operatorname{Var}(Y)>\operatorname{Var}(X)$$

Proposition 34.1:对任意彩票 \(F_X,F_Y\),\(F_Y\) 是 \(F_X\) 的均值保持展宽,若(\(X\sim F_X\)、\(Y\sim F_Y\))

$$Y=X+\varepsilon\qquad\text{with}\qquad\mathbb E[\varepsilon\mid X]=0.$$

Note

证明 / Proof(Prop 34.1:同均值 + 更大方差) 同均值:由迭代期望, $$\mathbb E[Y]=\mathbb E[\mathbb E[Y\mid X]]=\mathbb E[X+\mathbb E[\varepsilon\mid X]]=\mathbb E[X].$$ 更大方差:先算 $$\mathbb E[Y^2-X^2]=\mathbb E[\varepsilon^2]+2\mathbb E[\varepsilon X]=\mathbb E[\varepsilon^2]+2\mathbb E[\mathbb E[\varepsilon\mid X]X]=\mathbb E[\varepsilon^2]>0.$$ 再代回方差差值(用 \(\mathbb E[Y]=\mathbb E[X]\)): $$\operatorname{Var}(Y)-\operatorname{Var}(X)=\underbrace{\mathbb E[Y^2]-\mathbb E[X^2]}_{>0}\ \underbrace{-\,\mathbb E[Y]^2+\mathbb E[X]^2}_{=0}>0.$$ 故 \(F_Y\) 确为 \(F_X\) 的均值保持展宽。\(\blacksquare\)

34.3 Condition for Second-Order Stochastic Dominance

Theorem 34.1:若 \(\mathbb E[Y\mid X]=X\),\(X\sim F_X\)、\(Y\sim F_Y\),则 \(F_X\ge_{\text{SOSD}}F_Y\)。

Note

证明 / Proof(Theorem 34.1) 设 \(Y=X+\varepsilon\),则 \(\mathbb E[Y\mid X]=X\) 蕴含 \(\mathbb E[\varepsilon\mid X]=0\)。对任意递增且凹的 \(u(\cdot)\): $$\mathbb E[u(Y)]=\mathbb E[u(X+\varepsilon)]=\mathbb E[\mathbb E[u(X+\varepsilon)\mid X]]\le\mathbb E[u(\mathbb E[X+\varepsilon\mid X])]=\mathbb E[u(\mathbb E[Y\mid X])]=\mathbb E[u(X)],$$ 其中第三步用迭代期望、不等式用 Jensen 不等式(\(u\) 凹)。于是 $$\int u(x)\,dF_X(x)\ \ge\ \int u(y)\,dF_Y(y),$$ 由定义直接得 \(F_X\ge_{\text{SOSD}}F_Y\)。\(\blacksquare\)

Tip

Remark 34.2 显然 \(Y\) 是 \(X\) 的均值保持展宽。由此可见风险厌恶者总是不喜欢均值保持展宽这一直觉是对的。(由 (32.12) 可立即看出:对风险厌恶者,确定性等价随方差增大而递减。)

Proposition 34.1: for any lotteries \(F_X,F_Y\), \(F_Y\) is a mean-preserving spread of \(F_X\) if (with \(X\sim F_X\), \(Y\sim F_Y\))

$$Y=X+\varepsilon\qquad\text{with}\qquad\mathbb E[\varepsilon\mid X]=0.$$

Note

证明 / Proof (Prop 34.1: same mean + larger variance) Same mean: by iterated expectation, $$\mathbb E[Y]=\mathbb E[\mathbb E[Y\mid X]]=\mathbb E[X+\mathbb E[\varepsilon\mid X]]=\mathbb E[X].$$ Larger variance: first compute $$\mathbb E[Y^2-X^2]=\mathbb E[\varepsilon^2]+2\mathbb E[\varepsilon X]=\mathbb E[\varepsilon^2]+2\mathbb E[\mathbb E[\varepsilon\mid X]X]=\mathbb E[\varepsilon^2]>0.$$ Then substitute back into the variance difference (using \(\mathbb E[Y]=\mathbb E[X]\)): $$\operatorname{Var}(Y)-\operatorname{Var}(X)=\underbrace{\mathbb E[Y^2]-\mathbb E[X^2]}_{>0}\ \underbrace{-\,\mathbb E[Y]^2+\mathbb E[X]^2}_{=0}>0.$$ So \(F_Y\) is indeed a mean-preserving spread of \(F_X\). \(\blacksquare\)

34.3 Condition for Second-Order Stochastic Dominance

Theorem 34.1: if \(\mathbb E[Y\mid X]=X\), \(X\sim F_X\) and \(Y\sim F_Y\), then \(F_X\ge_{\text{SOSD}}F_Y\).

Note

证明 / Proof (Theorem 34.1) Suppose \(Y=X+\varepsilon\), then \(\mathbb E[Y\mid X]=X\) implies \(\mathbb E[\varepsilon\mid X]=0\). For any increasing and concave \(u(\cdot)\): $$\mathbb E[u(Y)]=\mathbb E[u(X+\varepsilon)]=\mathbb E[\mathbb E[u(X+\varepsilon)\mid X]]\le\mathbb E[u(\mathbb E[X+\varepsilon\mid X])]=\mathbb E[u(\mathbb E[Y\mid X])]=\mathbb E[u(X)],$$ where the third step uses the law of iterated expectation and the inequality uses Jensen's inequality (\(u\) concave). Hence $$\int u(x)\,dF_X(x)\ \ge\ \int u(y)\,dF_Y(y),$$ which by definition directly proves \(F_X\ge_{\text{SOSD}}F_Y\). \(\blacksquare\)

Tip

Remark 34.2 Clearly \(Y\) is a mean-preserving spread of \(X\). So we can see the intuition that risk-averse agents always dislike mean-preserving spreads is correct. (From (32.12) we immediately see: for risk-averse agents, the certainty equivalence is decreasing in variance.)

Example 34.1 — Optimal Portfolio of i.i.d. Assets

(定理 34.1 的应用) 考虑一个单期问题。有 \(N\) 个具有 i.i.d. 毛收益 \(R_1,\dots,R_N\) 的资产。若代理人风险厌恶(\(u'(\cdot)>0\)、\(u''(\cdot)<0\)),求最优组合权重。

猜测 (Guess):每个资产的最优权重为 \(\frac1N\),即最优组合的毛收益为

$$Y^\star=\frac1N\sum_{i=1}^N R_i.$$

验证 (Verify):考虑任意另一组合,权重 \(\{w_i\}_{i=1}^N\)(\(\sum_i w_i=1\)),其收益为 \(Y\equiv\sum_{i=1}^N w_iR_i\)。记 \(Y^\star\sim F_{Y^\star}\)、\(Y\sim F_Y\)。欲证 \(Y^\star\) 对任意风险厌恶者最优,即对 \(\forall\{w_i\}\) 都有 \(F_{Y^\star}\ge_{\text{SOSD}}F_Y\)。

由定理 34.1,只需证 \(\mathbb E[Y\mid Y^\star]=Y^\star\),即

$$\mathbb E\!\left[\sum_{i=1}^N w_iR_i\ \Big|\ Y^\star\right]=Y^\star.$$

定义 \(K(Y^\star)\equiv\mathbb E[R_i\mid Y^\star]\)(由 i.i.d. 对称性,对所有 \(i\) 相同)。则

$$\mathbb E\!\left[\sum_{i=1}^N w_iR_i\ \Big|\ Y^\star\right]=\sum_{i=1}^N w_i\,\mathbb E[R_i\mid Y^\star]=\sum_{i=1}^N w_i\,K(Y^\star)=K(Y^\star),$$

最后一步用 \(\sum_i w_i=1\)。故只需证 \(K(Y^\star)=Y^\star\)。注意

$$K(Y^\star)=\frac1N\sum_{i=1}^N K(Y^\star)=\frac1N\sum_{i=1}^N\mathbb E[R_i\mid Y^\star]=\mathbb E\!\left[\frac1N\sum_{i=1}^N R_i\ \Big|\ Y^\star\right]=\mathbb E[Y^\star\mid Y^\star]=Y^\star.$$

故 \(\mathbb E[Y\mid Y^\star]=Y^\star\),由定理 34.1 得 \(F_{Y^\star}\ge_{\text{SOSD}}F_Y\)——等权组合对任意风险厌恶者都是最优的。证毕。

(Application of theorem 34.1) Consider a one-period problem. There are \(N\) assets with i.i.d. gross returns \(R_1,\dots,R_N\). Solve for the best portfolio weights if the agent is risk averse (\(u'(\cdot)>0\), \(u''(\cdot)<0\)).

Guess: the optimal weight for each asset is \(\frac1N\), i.e. the gross return of the optimal portfolio is

$$Y^\star=\frac1N\sum_{i=1}^N R_i.$$

Verify: consider any other portfolio with weights \(\{w_i\}_{i=1}^N\) (\(\sum_i w_i=1\)), whose return is \(Y\equiv\sum_{i=1}^N w_iR_i\). Denote \(Y^\star\sim F_{Y^\star}\) and \(Y\sim F_Y\). To prove \(Y^\star\) is optimal for any risk-averse agent, we want to show \(F_{Y^\star}\ge_{\text{SOSD}}F_Y\) for all \(\{w_i\}\).

By theorem 34.1, it's enough to show \(\mathbb E[Y\mid Y^\star]=Y^\star\), i.e.

$$\mathbb E\!\left[\sum_{i=1}^N w_iR_i\ \Big|\ Y^\star\right]=Y^\star.$$

Define \(K(Y^\star)\equiv\mathbb E[R_i\mid Y^\star]\) (the same for all \(i\) by i.i.d. symmetry). Then

$$\mathbb E\!\left[\sum_{i=1}^N w_iR_i\ \Big|\ Y^\star\right]=\sum_{i=1}^N w_i\,\mathbb E[R_i\mid Y^\star]=\sum_{i=1}^N w_i\,K(Y^\star)=K(Y^\star),$$

the last step using \(\sum_i w_i=1\). So we only need to show \(K(Y^\star)=Y^\star\). Note that

$$K(Y^\star)=\frac1N\sum_{i=1}^N K(Y^\star)=\frac1N\sum_{i=1}^N\mathbb E[R_i\mid Y^\star]=\mathbb E\!\left[\frac1N\sum_{i=1}^N R_i\ \Big|\ Y^\star\right]=\mathbb E[Y^\star\mid Y^\star]=Y^\star.$$

So \(\mathbb E[Y\mid Y^\star]=Y^\star\), and by theorem 34.1, \(F_{Y^\star}\ge_{\text{SOSD}}F_Y\) — the equal-weight portfolio is optimal for any risk-averse agent. Done.

References

  • He, X. (2020–2024). Asset Pricing (lecture notes), Ch. 34.